∵和滚∠ADE=∠DAC∴DE‖AC∴∠BDE=∠C∵∠B+∠BED=∠ADE+∠ADC, ∠卜棚正B=∠ADE∴∠BED=∠型悔ADC∴三个角均相等,△EBD∽△ADC设BD:BC=X:1 (0∴BD:BC=BE:AB=DE:AC=X, BD:AC=BE:AD=DE:CD=X/(1-X)∴m1=Xm, m2=(1-X)m1/X=(1-X)m∴(m1+m2)/m=(x+1-x)m/m=1∴(m1+m2)/m最大值1