解:∵焦点为F1(0,-5)和F2(0,5)∴c=5∴b^2=c^2-a^2=25-a^2设双曲线的标准方兄棚程为y^2/a^2-x^2/b^2=1(a>0,b>0).(焦点在y轴上)由b^2=25-a^2,方程可变羡枣则为y^2/(a^2)-x^2/(25-a^2)=1.∵方程过点A(0,3)∴9/(a^2)=1∴a^2=9,b^2=16∴双岩旦曲线的标准方程为y^2/9-x^2/16=1.
y^2/9-x^2/16=1