z = - 1/2 (1+i)
设z=a+bi
a+bi+(a+bi)(a-bi)=1/缓闭4(1-i)^2
a+bi+a^2+b^2=-1/2i
a+a^2+b^2=0,b=-1/2
解得扰梁裂a=-1/2,b=-1/渣岩2
z=-1/2-1/2i
设Z=a+bi
则左面=a+bi+(a+bi)(a-bi)=a+a^2+b^2+bi
右面=1/4(1-1-2i)=-1/2 i
则枯亩扮 b=-1/没灶耐告2 a+a^2+b^2=0 a=-1/2
Z=(-1/2)+(-1/2) i
z=a+bi 共轭陵扒复数z'姿汪坦=a-bi
a+bi+a^2+b^2=1/4(1-i)^2
a+bi+a^2+b^2=1/4(-2i)
a+a^2+b^2=0
b=-1/2
a+a^2+1/4=0
(a+1/2)^2=0,a=-1/2
z=-1/2-1/迹桐2i