设上为①胡磨旦式,下为②①-②*2 得 x^2-x=0; 解得x=1或x=0;将x=1代回②式得 y-2y-3=0 即(y-3)(y+1)=0,解得y=3 或y=-1将游搭x=0代回②式得 y-2y=0 即裤扰y(y-2)=0, 解得y=0或y=2;